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If (x2 – 1) is a factor of ax4 + bx3 + cx2 + dx + e, then :(a) a + c + e = 0 (b) ace = 1 (c) b + d = 0 (d) Both (a) and (c) |
Answer» (d) Both (a) and (c) Let f(x) = ax4 + bx4 + cx2 + dx + e be the given polynomial. Then, (x2 – 1) is a factor of f(x). ⇒ (x – 1) (x + 1) is a factor of f(x) ⇒ (x – 1) and (x + 1) are factors of f(x) ⇒ f(1) = 0 and f(–1) = 0 ⇒ a + b + c + d + e = 0 and a – b + c – d + e = 0. Adding and subtracting the two equations, we get 2(a + c + e) = 0 and 2(b + d) = 0 ⇒ a + c + e = 0 and b + d = 0. |
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