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If ∫√x2−14dx=Ax√x2−14+Bln∣∣x+√x2−14∣∣+C (where A,B are fixed constants and C is integration constant). Then the value of ∣∣∣BA∣∣∣ is

Answer» If x214dx=Axx214+Blnx+x214+C (where A,B are fixed constants and C is integration constant). Then the value of BA is


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