If x2 + \(\frac{1}{x^2}\) = 62 then x + \(\frac{1}{x}\) = ……….

1.	If x2 + \(\frac{1}{x^2}\) = 62 then x + \(\frac{1}{x}\) = ……….. (x + \(\frac{1}{x}\)> 0) A) 3 B) 8 C) 4 D) 6
Answer» Correct option is B) 8 Correct option is (B) 8 \(x^2+\frac1{x^2}\) = 62 \(\Rightarrow\) \(x^2+\frac1{x^2}+2=62+2\) \(\Rightarrow\) \((x+\frac1x)^2=64=8^2\) \(\Rightarrow\) \(x+\frac1x\) = 8 \((\because\) \(x+\frac1x\) > 0)

If x2 + \(\frac{1}{x^2}\) = 62 then x + \(\frac{1}{x}\) = ……….. (x + \(\frac{1}{x}\)> 0) A) 3 B) 8 C) 4 D) 6

Answer»

Correct option is B) 8

Correct option is (B) 8

\(x^2+\frac1{x^2}\) = 62

\(\Rightarrow\) \(x^2+\frac1{x^2}+2=62+2\)

\(\Rightarrow\) \((x+\frac1x)^2=64=8^2\)

\(\Rightarrow\) \(x+\frac1x\) = 8 \((\because\) \(x+\frac1x\) > 0)