If x2−x+1=0 then the value of (x+1x)2+(x2+1x2)2+(x3+1x3)2+(x5+1x5)2 – InterviewSolution

1.	If x2−x+1=0 then the value of (x+1x)2+(x2+1x2)2+(x3+1x3)2+(x5+1x5)2 is
Answer» If $x^{2} - x + 1 = 0$ then the value of ${(x + \frac{1}{x})}^{2} + {(x^{2} + \frac{1}{x^{2}})}^{2} + {(x^{3} + \frac{1}{x^{3}})}^{2} + {(x^{5} + \frac{1}{x^{5}})}^{2}$ is

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