If x2+y2+z2 = 29 and xy + yz + zx = 26 , then the value of x + y + z i

1.	If x2+y2+z2 = 29 and xy + yz + zx = 26 , then the value of x + y + z is: (A) 9 (B) 81 (C) +9 (D) +3
Answer» (C) x²+ y²+ z² = 29 xy + yz + zx = 26 x²+ y²+ z²= 2xy + 2yz + 2zx = 29 + 2 x 26 = 81 ∴ (x + y + z)² = 81 x + y + z = +9

If x2+y2+z2 = 29 and xy + yz + zx = 26 , then the value of x + y + z is: (A) 9 (B) 81 (C) +9 (D) +3

Answer»

(C)

x²+ y²+ z² = 29

xy + yz + zx = 26

x²+ y²+ z²= 2xy + 2yz + 2zx

= 29 + 2 x 26 = 81

∴ (x + y + z)² = 81

x + y + z = +9

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If x2+y2+z2 = 29 and xy + yz + zx = 26 , then the value of x + y + z is: (A) 9 (B) 81 (C) +9 (D) +3

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