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If x3 + 6x2 + kx + 6 is exactly divisible by (x + 2), then k = ? (1) -6 (2) -7 (3) -8 (4) 11 |
Answer» (4) 11 P(-2) = (-2)3 + 6 (-2)2 + k (-2) + 6 = 0 ⇒ – 8 + 24 – 2k +6 = 0 ⇒ 22 = 2k ⇒ k = 11 |
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