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If `xa n dy`are positive acute angles such that `(x+y)`and `(x-y)`satisfy the equation `tan^2theta-4tantheta+1=0,`then`x=pi/6`(b) `y=pi/4`(c) `y=pi/6`(d) `y=pi/4`A. `x=pi/6`B. `y=pi/4`C. `y=pi/6`D. `x=pi/4` |
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Answer» Correct Answer - C::D `(x+y)` and `(x-y)` satisfy the equation `tan^(2) theta-4 tan theta+1=0`. Thus, `tan (x+y)+tan (x-y)=4` and `tan (x+y)tan (x-y)=1` `:. Tan2x=tan ((x+y)+(x-y))` or `tan 2x= (tan (x+y)+tan (x-y))/(1-tan (x+y) tan (x-y))` `:. Tan2x=oo` or `2x=90^(@)` or `x=45^(@)=pi/4` `:. y=pi/6` |
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