1.

If xacos θ+ybsin θ=1and xasin θ−ybcos θ=1,prove that x2a2+y2b2=2

Answer»

If xacos θ+ybsin θ=1and xasin θybcos θ=1,prove that x2a2+y2b2=2



Discussion

No Comment Found

Related InterviewSolutions