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If `xcostheta-sintheta=1," then "x^(2)-(1+x^(2))sintheta` equalsA. 1B. -1C. 0D. 2 |
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Answer» Correct Answer - a Given let x=1 and `theta=0^(@)` `rArrx cos theta-sintheta+1`..........(i) `rArr1xx1-(0)=1` `rArr1=1` putting value `x=1` and `theta=0^(@)` in following equation `rArrx^(2)-(1+x^(2))sintheta` `rArr1^(2)-(1+1^(2))xx sin0^(@)` =1 |
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