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If ∫xe−1+ex−1xe+exdx=kln|xe+ex|+C, then the value of 4lnk+7 is equal to(where C is constant of integration) |
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Answer» If ∫xe−1+ex−1xe+exdx=kln|xe+ex|+C, then the value of 4lnk+7 is equal to (where C is constant of integration) |
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