1.

If ∫xe−1+ex−1xe+exdx=kln|xe+ex|+C, then the value of 4lnk+7 is equal to(where C is constant of integration)

Answer» If xe1+ex1xe+exdx=kln|xe+ex|+C, then the value of 4lnk+7 is equal to

(where C is constant of integration)


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