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If ∫√xx+1dx=A√x+Btan−1√x+C, then |A|+|B| is equal to(where C is integration constant and A and B are fixed constants) |
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Answer» If ∫√xx+1dx=A√x+Btan−1√x+C, then |A|+|B| is equal to (where C is integration constant and A and B are fixed constants) |
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