1.

If xy+yx=−1, where x,y≠0 then the value of (x3−y3) is (a) 1 (b)−1 (c) 0(d) 12

Answer»

If xy+yx=1, where x,y0 then the value of (x3y3) is
(a) 1

(b)1

(c) 0

(d) 12



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