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If `y=(1)/(sqrtx)=(x)^(-1//2)`, then find `dy//dx`. |
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Answer» Differentiating both sides w.r.t. x, we get `(dy)/(dx)=(d[(x)^(-1//2)])/(dx)=-1/2x^(-(1//2)-1)=-1/2x^(-3//2)=-(1)/(2x^(3//2))` |
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