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If `y=3x^2+2x`, then find `dy//dx`. |
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Answer» `(dy)/(dx)=(d)/(dx)[3x^2]+(d)/(dx)[2x]` (Using the linearity property of differentiation) `(dy)/(dx)=3(d[x^2])/(dx)+2(d[x])/(dx)` (Separating the constant coefficients) `=3xx2x^(2-1)+2xx1x^(1-1)=6x+2` `("Using" (d[x^(n)])/(dx)=nx^(n-1))` |
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