If y = 5cosø - 3sinøThen prove that d^2 y / dx^2 +y = 0

1.	If y = 5cosø - 3sinøThen prove that d^2 y / dx^2 +y = 0
Answer» It\'s simpledy/dx = -5sin-3cosd2y/dx^2 = -5cos+3sinAdding y both side we getD^2y/dx^2 +y=0<br>Hey

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