If `y+a=m_(1)(x+3a),y+a=m_(2)(x+3a)` are two tangents to the parabola `y^(2)=4ax`, thenA. `m_(1)+m_(2)+m_(1)m_(2)=0`B. `m_(1)+m_(2)-m_(1)m_(2)=2/3`C. `m_(1)+m_(2)+2m_(1)m_(2)=1/3`D. `m_(1)+m_(2)-2m_(1)m_(2)=1`

If `y+a=m_(1)(x+3a),y+a=m_(2)(x+3a)` are two tangents to the parabola

1.	If `y+a=m_(1)(x+3a),y+a=m_(2)(x+3a)` are two tangents to the parabola `y^(2)=4ax`, thenA. `m_(1)+m_(2)+m_(1)m_(2)=0`B. `m_(1)+m_(2)-m_(1)m_(2)=2/3`C. `m_(1)+m_(2)+2m_(1)m_(2)=1/3`D. `m_(1)+m_(2)-2m_(1)m_(2)=1`
Answer» Correct Answer - A::B::D Let equation of tangent is `y=mx+a/m` `implies-a=-3am+a/m` `implies3m^(2)-m-1=0` `m_(1)+m_(2)=1/3,m_(1),m_(2)=-1/3`

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If `y+a=m_(1)(x+3a),y+a=m_(2)(x+3a)` are two tangents to the parabola `y^(2)=4ax`, thenA. `m_(1)+m_(2)+m_(1)m_(2)=0`B. `m_(1)+m_(2)-m_(1)m_(2)=2/3`C. `m_(1)+m_(2)+2m_(1)m_(2)=1/3`D. `m_(1)+m_(2)-2m_(1)m_(2)=1`

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