1.

If Y and B represent Young's modulus and bulb modulus for a material, then in partice

Answer»

`Y LT 3B`
`Y = 3B`
`Y gt 3B`
`B= 3Y`

Solution :`(Y)/(3B) = 1-2 SIGMA`
But `sigma`, in practice LIES between zero and `(1)/(2)`, so `0 lt 1 - 2sigma lt 1`
Hence, `(Y)/(3B) lt 1 or Y lt 3B`


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