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If `y=ax^(2)+bx+c` is the reflection of parabola `y=x^(2)-4x+1` about the line `y=3,a+b+c=`A. 1B. 2C. 3D. 4 |
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Answer» Correct Answer - B `sqrt((x+3)(x-2))-(x-2)=sqrt((x-2)(x-5))` For the equation to be defined `x in (-oo,-3] uu [2,oo)" and "x in (-oo,2]uu[5,oo)` `therefore x in (-oo,-3]uu[5,oo)uu{2}` On solving we get `x=2,6,-(10)/(3)` |
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