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If y=ax2(x−a)(x−b)(x−c)+bx(x−b)(x−c)+cx−c+1, then y′y is equal to(Here, y′=dydx) |
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Answer» If y=ax2(x−a)(x−b)(x−c)+bx(x−b)(x−c)+cx−c+1, then y′y is equal to |
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