1.

If y=ax2(x−a)(x−b)(x−c)+bx(x−b)(x−c)+cx−c+1, then y′y is equal to(Here, y′=dydx)

Answer»

If y=ax2(xa)(xb)(xc)+bx(xb)(xc)+cxc+1, then yy is equal to

(Here, y=dydx)



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