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If `y = e^(x). cot x` then `(dy)/(dx)` will beA. `e^(x) cot x- cosec^(2) x`B. `e^(x) cosec^(2) x`C. `e^(x)[cot x- cosec^(3) x]`D. `e^(x) cot x` |
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Answer» Correct Answer - C `y=e_(x),(d)/(dx)cotx` `(dy)/(dx)=e_(x)(cot x)+cot x(d)/(dx)(e_(x))` `=e_(x)(-cosec_(2)x)+ cot x e_(x)` `= e_(x)[cor x- cosec_(2) x]`. |
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