1.

If `y=e^(x).cotx` then `(dy)/(dx)` will beA. `e^(x)cot x-cosec^(2)x`B. `e^(x) cosec^(2)x`C. `e^(x)[cot x-cosec^(2)x]`D. `e^(x)cot x`

Answer» Correct Answer - C
`y=e^(x).cotx`
`(dy)/(dx)=e^(x)(d)/(dx)(cotx)+cotx(d)/(dx)(e^(x))`
`=e^(x)(-cosec^(2)x)+cotxe^(x)`
`=e^(x)[cotx-cosec^(2)x]`


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