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If `y=e^(x).cotx` then `(dy)/(dx)` will beA. `e^(x)cot x-cosec^(2)x`B. `e^(x) cosec^(2)x`C. `e^(x)[cot x-cosec^(2)x]`D. `e^(x)cot x` |
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Answer» Correct Answer - C `y=e^(x).cotx` `(dy)/(dx)=e^(x)(d)/(dx)(cotx)+cotx(d)/(dx)(e^(x))` `=e^(x)(-cosec^(2)x)+cotxe^(x)` `=e^(x)[cotx-cosec^(2)x]` |
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