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If \( y=\frac{(x-a)(x-b)}{(x-c)(x-d)} \) find \( \frac{d y}{d x} \) |
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Answer» \(y = \frac{(x - a) (x - b)}{(x-c)(x - d)}\) \(log \,y = log(x -a) + log(x - b) - log(x - c) - log(x - d)\) \(\frac1y \frac{dy}{dx} = \frac1{x - a} + \frac1 {x - b} -\frac1{x - c} - \frac1{x - d}\) \(\therefore \frac{dy}{dx} = \frac{(x - a) (x - b)}{(x-c)(x - d)}\left( \frac1{x - a} + \frac1 {x - b} -\frac1{x - c} - \frac1{x - d}\right)\) |
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