If y = log(cosex), then dy/dx is :(a) cos ex−1(b) e-x cos ex(c) ex

1.	If y = log(cosex), then dy/dx is :(a) cos ex−1(b) e-x cos ex(c) ex sin ex (d) − ex tanex
Answer» Option : (d) y = log(cose^x) Differentiating wrt x : \(\frac{dy}{dx}\) = \(\frac{1}{cos(e^x)}.\) (-sin e^x) . e^x(chain rule) ⇒ \(\frac{dy}{dx}\) = −e^x tan e^x

If y = log(cosex), then dy/dx is :(a) cos ex−1(b) e-x cos ex(c) ex sin ex (d) − ex tanex

Answer»

Option : (d)

y = log(cose^x)

Differentiating wrt x :

\(\frac{dy}{dx}\) = \(\frac{1}{cos(e^x)}.\) (-sin e^x) . e^x(chain rule)

⇒ \(\frac{dy}{dx}\) = −e^x tan e^x

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If y = log(cosex), then dy/dx is :(a) cos ex−1(b) e-x cos ex(c) ex sin ex (d) − ex tanex

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