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If y=mx−b√1+m2 is a common tangent to x2+y2=b2 and (x−a)2+y2=b2, where a>2b>0, then the positive value of m is |
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Answer» If y=mx−b√1+m2 is a common tangent to x2+y2=b2 and (x−a)2+y2=b2, where a>2b>0, then the positive value of m is |
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