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If y = sin-1(3x - 4x3) then dy/dx = ?A. 3/√1-x2B. -4/√1-x2C. 3/√1+x2D. none of these |
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Answer» Answer is: 3/√1-x2 Given that y = sin-1(3x - 4x3) Let x = sin θ ⇒ θ = sin-1x Then, y = sin-1(3sinθ - 4sin3θ) Using sin3θ = 3sinθ - 4sin 3θ, we get y = sin-1(sin3θ) = 3θ = 3sin-1x Differentiating with respect to x, we get dy/dx = 3/√1-x2 |
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