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If `y=t^(3)//3-t^(2)-3t+1` then graph of `y_(2)` versus t will be, where `y_(2)=d^(2)y//dt^(2)`A. B. C. D. |
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Answer» `(dy)/(dt)=t^(2)-2t-3` `(d^(2)y)/(dt^(2))=2t-2` |
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