If y(t) is a solution of (1+t)dydt−ty=1,t≥0 and y(0)=−1,y(1)=α, – InterviewSolution

1.	If y(t) is a solution of (1+t)dydt−ty=1,t≥0 and y(0)=−1,y(1)=α, then 2α+1 is
Answer» If $y (t)$ is a solution of $(1 + t) \frac{d y}{d t} - t y = 1, t \geq 0$ and $y (0) = - 1, y (1) = α,$ then $2 α + 1$ is

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