Saved Bookmarks
| 1. |
If y=x-1/2x^(2) is the equation of a trajectory, find the time of flight. |
|
Answer» Solution :We have `y=X-1/2x^(2)-x(1-x//2)` If y=0, then either x=0 or x=2 HENCE the arange of the motion is 2. For HALF the range x=1 then `y=1//2` Hence maximum height attained `=1//2` Time to reach maximum height `t=sqrt((2Y)/g)=sqrt(1/g)` Time of FLIGHT `T=2t=2sqrt(1/g)` i.e. `T=2/(sqrt(g))` |
|