1.

If y=x√a2−1−2√a2−1tan−1(sinxa+√a2−1+cosx) where a∈(−∞,−1)∪(1,∞), then y′(π2) is equal to

Answer»

If y=xa212a21tan1(sinxa+a21+cosx) where a(,1)(1,), then y(π2) is equal to



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