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If y=x√a2−1−2√a2−1tan−1(sinxa+√a2−1+cosx) where a∈(−∞,−1)∪(1,∞), then y′(π2) is equal to |
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Answer» If y=x√a2−1−2√a2−1tan−1(sinxa+√a2−1+cosx) where a∈(−∞,−1)∪(1,∞), then y′(π2) is equal to |
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