If y=x5(cos(lnx)+sin(lnx)), then the value of (a+b) in the relation x2 – InterviewSolution

1.	If y=x5(cos(lnx)+sin(lnx)), then the value of (a+b) in the relation x2y2+axy1+by=0 is (y1 and y2 denote the first and second derivative of y with respect to x, respectively.)
Answer» If $y = x^{5} (cos (ln x) + sin (ln x))$ , then the value of $(a + b)$ in the relation $x^{2} y_{2} + a x y_{1} + b y = 0$ is $(y_{1}$ and $y_{2}$ denote the first and second derivative of $y$ with respect to $x$ , respectively. $)$

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