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if `y=y(x)`and `(2+sinx)/(y+1)((dy)/(dx))=-cosx ,y(0)=1,`then `y(pi/2)=`(a)`( b ) (c) (d)1/( e )3( f ) (g) (h)`(i)(b) `( j ) (k) (l)2/( m )3( n ) (o) (p)`(q)(c) `( r ) (s)-( t )1/( u )3( v ) (w) (x)`(y) (d)1A. (a) 1/3B. (b) 2/3C. (c) -1/3D. (d) 1 |
Answer» Correct Answer - (a) Given, `dy/dx=(-cosx(y+1))/(2+sin x)` `rArr dy/(y+1)=(-cosx)/(2+sinx)dx` On integrating both sides `int dy/(y+1)=-int (cosx)/(2+sinx)dx` `rArr log (y+1)=-log(2+sin x) +log e` When `x =0, y=1 rArr c = 4` `rArr y+1=4/(2+sin x` `therefore y(pi/2)=4/3-1` `rArr y(pi/2)=1/3` |
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