1.

if `y=y(x)`and `(2+sinx)/(y+1)((dy)/(dx))=-cosx ,y(0)=1,`then `y(pi/2)=`(a)`( b ) (c) (d)1/( e )3( f ) (g) (h)`(i)(b) `( j ) (k) (l)2/( m )3( n ) (o) (p)`(q)(c) `( r ) (s)-( t )1/( u )3( v ) (w) (x)`(y) (d)1A. (a) 1/3B. (b) 2/3C. (c) -1/3D. (d) 1

Answer» Correct Answer - (a)
Given, `dy/dx=(-cosx(y+1))/(2+sin x)`
`rArr dy/(y+1)=(-cosx)/(2+sinx)dx`
On integrating both sides
`int dy/(y+1)=-int (cosx)/(2+sinx)dx`
`rArr log (y+1)=-log(2+sin x) +log e`
When `x =0, y=1 rArr c = 4`
`rArr y+1=4/(2+sin x`
`therefore y(pi/2)=4/3-1`
`rArr y(pi/2)=1/3`


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