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If y=y(x) is the solution of the differential equation dydx+(tanx)y=sinx,0≤x≤π3, with y(0)=0, then y(π4) equal to : |
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Answer» If y=y(x) is the solution of the differential equation dydx+(tanx)y=sinx,0≤x≤π3, with y(0)=0, then y(π4) equal to : |
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