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If y=y(x) is the solution of the equation esinycosydydx+esinycosx=cosx, y(0)=0; then 1+y(π6)+√32y(π3)+1√2y(π4) is equal to |
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Answer» If y=y(x) is the solution of the equation esinycosydydx+esinycosx=cosx, y(0)=0; then 1+y(π6)+√32y(π3)+1√2y(π4) is equal to |
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