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If [(y/z)to the power a [(z/x)to the power b][(x/y) to the powerc]= 1, then prove that [(y/z)to the power 1/b-c] =[(z/x)to the power 1/c-a] = [(x/y)to the power 1/a-b] |
| Answer» If [(y/z)to the power a [(z/x)to the power b][(x/y) to the powerc]= 1, then prove that [(y/z)to the power 1/b-c] =[(z/x)to the power 1/c-a] = [(x/y)to the power 1/a-b] | |