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If y1(x) is a solution of the differential equation dydx−f(x)y=0, then a solution of the differential equation dydx+f(x)y=r(x) |
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Answer» If y1(x) is a solution of the differential equation dydx−f(x)y=0, then a solution of the differential equation dydx+f(x)y=r(x) |
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