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If y2 = 4ax then \(\rm \frac{dy}{dx} = \)1. 4a2. \(\rm \frac{4a}{y}\)3. \(\rm \frac{2a}{y}\)4. 2a |
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Answer» Correct Answer - Option 3 : \(\rm \frac{2a}{y}\) Concept: \(\rm \frac{dx^n}{dx}=nx^{n-1}\)
Calculation: Given: y2 = 4ax Differentiating with respect to x, we get \(\rm \Rightarrow {2y}\frac{dy}{dx} = 4a\) \(\rm \Rightarrow \frac{dy}{dx} = \frac{4a}{{2y}} \) \(\rm \therefore \frac{dy}{dx} = \frac{2a}{y} \) |
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