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If you throw a pair of dice n times, find the probability of getting at least one doublet.[When you get identical members you call it a doublet. You can get a double in six ways: (1,1),(2,2),(3,3),(4,4),(5,5) and (6,6) , thus the probability of getting a doublet is 6/36=1/6, so that the probability of not getting a doublet in one throw is 5/6]. |
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Answer» Solution :A PAIR od DICE is thrown n times. We get the doublet as (1,1),(2,2),(3,3),(4,4),(5,5),(6,6). `therefore` PROBABILITY of getting a doublet in one throw `=6/36=1/6` `therefore` Probability of not getting a doublet `=1-1/6=5/6` If a pair of dice is known n-times, the probability of not getting a doublet `=(5/6)^n` `therefore` Probability of getting atleast one doublet `=1-(5/6)^n` |
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