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If Z = (1+ 2i)/(1 - (1 - i)2), then find Arg (Z). |
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Answer» Given Z = (1 + 2i)/(1 - (1 - i)2) = (1 + 2i)/(1 - (1 - 2i + i2)) = (1 + 2i)/(1 + 2i) = 1 = cos0° + isin0° ∴ Arg(Z) = 0° |
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