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If `z=((1+isqrt(3))/(1+i))^(25)`, then arg(z) is equal toA. `(pi)/(12)`B. `-(pi)/(12)`C. `(7pi)/(12)`D. `(3pi)/(12)` |
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Answer» Correct Answer - 1 `z=(1+isqrt3)^(25)/(1+i)^(25)=(2^(25).(e^(ipi//3))^(25))/(2^(25/2).(e^(ipi//4))^(25))` `=2^(25/2)e^(i((25pi)/(12)))=e^(25/(2))e^(i((pi)/(12)))` or `(2pi+(pi)/(12))=(25pi)/(12)` |
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