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If `z_1, z_2 in C , z_1^2 in R , z_1(z_1^2-3z_2^2)=2` and `z_2(3z_1^2-z_2^2)=11`, then the value of `z_1^2+z_2^2`isA. 10B. 12C. 5D. 8 |
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Answer» Correct Answer - C We have, `z_(1)(z_(1)^(2)-3z_(2)^2) = 2 " "(1)` `z_(2)(3z_(1)^(2)-z_(2)^(2)) = 11` multiplying (2) by I and adding it to (1), we get `z_(1)^(3) - 3z_(2)^(2)z_(1) + i(3z_(1)^(2)z_(2) - z_(2)^(3)) = 2 +11i` `rArr (z_(1) +iz_(2))^(3) = 2 + 11i" "(3)` Multiply (2) by i and subtracting it form (1), we get `z_(1)^(3) - 3z_(2)^(2)z_(1) - i(3z_(1)^(2)z_(2)-z_(2)^(2)) = 2- 11i` `rArr (z_(1) + iz_(2))^(3) = 2+ 11i` Multiplying (3) and (4), we get `(z_(1)^(2) + z_(2)^(2))^(3) = 2^(2) - 121i^(2) = 4 + 121 = 125` `rArr z_(1)^(2) + _(2)^(2) = 5` |
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