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If `|z_1 + z_2| = |z_1| + |z_2|` is possible if :A. `z_(2)=1`B. `z_(2)=(1)/(z_(1))`C. `"arg"(z_(1)) ="arg"(z_(2))`D. `|z_(1)|=|z_(2)|` |
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Answer» Correct Answer - C `|z_(1)+z_(2)|^(2)=(|z_(1)|+|z_(2)|)^(2)` `|z_(1)|^(2)+|z_(2)|^(2)+2|z_(1)||z_(2)|"cos"(0_(1)-0_(2))=|z_(1)|^(2)+|z_(2)|^(2)+2|z_(1)||z_(2)|` `"cos" (0_(1)-0_(2)) =1` `"Arg"(z_(1)) ="Arg"(z_(2))` |
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