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If `|z^2-1|=|z|^2+1`, then `z` lies on(a) a circle(b) the imaginary axis(c) the real axis(d) an ellipse |
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Answer» `|Z^2-1|=|Z^2|-1` `|(Z^2-1)^2|=(|Z^2|-1)^2` `(Z^2-1)(Z^2-1)=(1+ZZ)^2` `-(Z^2-2^2)=2*Z*Z` Re(Z)=0 Z lies on the imaginary axis. |
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