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If z=(4sin2θ−1)+i(cos2θ+1) is purely imaginary number, then the number of value(s) of θ∈[0,2nπ] where n∈I is |
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Answer» If z=(4sin2θ−1)+i(cos2θ+1) is purely imaginary number, then the number of value(s) of θ∈[0,2nπ] where n∈I is |
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