If Z is a compressibility factor, van der Waals equation at low pressu

1.	If Z is a compressibility factor, van der Waals equation at low pressure can be written as
Answer» `Z=1+(Pb)/(RT)` `Z=1+(RT)/(Pb)` `Z=1-(a)/(VRT)` `Z=1-(Pb)/(RT)` Solution :For 1 mole of a real gas, van der Waals equation is `(P+(a)/(V^(2)))(V-b)=RT` At low PRESSURE, V is LARGE and therefore, b can be neglected in comparison to V so that `V-b~-V`. HENCE, `(P+(a)/(V^(2)))V=RT` or `PV+(a)/(V)=RT" or " PV=RT-(a)/(V)` or `(PV)/(RT)=1-(a)/(VRT)" or " Z=1-(a)/(VRT)`

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