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If z is a point on the Argand plane such that |z-1|=1, then (z-2)/z is equal to |
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Answer» TAN(arg)Z So, LET `z-1=costheta+isintheta` `rArr z-2=sintheta//2(-sintheta//2+icostheta/2)` and `z=2costheta//2(costheta//2+isintheta//2)` and, `z=2costheta//2(costheta//2+isintheta//2)` `rArr (z-2)/(z)=i{(costheta/2+isintheta/2)/(costheta/2+isintheta/2)}tantheta/2` `rArr (z-2)/z = itantheta/2 rArr (z-2)/z=i tan(arg z)` |
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