If Z1 = 1 – 3i, z2 = -4i, and z3 = 5, show that (z1 + z2 ) + z3 =

1.	If Z1 = 1 – 3i, z2 = -4i, and z3 = 5, show that (z1 + z2 ) + z3 = Z1 + (z2 + z3 )
Answer» Z₁ = 1 – 3i, z₂ = -4i, z₃ = 5, (z₁ + z₂ ) + z₃ =(1 – 3i – 4i) + 5(1 – 7i) + 5 = 6 – 7i …..(1) Z₁ + (z₂ + z₃ ) = (1 – 3i) + (-4i + 5) = 6 – 7i …..(2) from(1)& (2) we get ∴ (z₁ + z₂ ) + z₃ = z₁ + (z₂ + z₃ )

If Z1 = 1 – 3i, z2 = -4i, and z3 = 5, show that (z1 + z2 ) + z3 = Z1 + (z2 + z3 )

Answer»

Z₁ = 1 – 3i, z₂ = -4i, z₃ = 5,

(z₁ + z₂ ) + z₃ =(1 – 3i – 4i) + 5(1 – 7i) + 5

= 6 – 7i …..(1)

Z₁ + (z₂ + z₃ ) = (1 – 3i) + (-4i + 5)

= 6 – 7i …..(2)

from(1)& (2) we get

∴ (z₁ + z₂ ) + z₃ = z₁ + (z₂ + z₃ )

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If Z1 = 1 – 3i, z2 = -4i, and z3 = 5, show that (z1 + z2 ) + z3 = Z1 + (z2 + z3 )

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