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If z1,z2,⋯zn lie on the circle |z|=2 then the value of |z1+z2+⋯+zn|−4∣∣∣1z1+1z2+⋯+1zn∣∣∣=

Answer»

If z1,z2,zn lie on the circle |z|=2 then the value of |z1+z2++zn|41z1+1z2++1zn=



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