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If (z3 + 1z3) - (z2 + 1z2) + (z+1z) - 1 = (z+1z−2α) (z+1z−2β) (z+1z−2γ) Find the value of α.β.γ. |
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Answer» If (z3 + 1z3) - (z2 + 1z2) + (z+1z) - 1 = (z+1z−2α) (z+1z−2β) (z+1z−2γ) Find the value of α.β.γ. |
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