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If1/a,1/b,1/c are in A.P. and a+b+cne0_2 prove that (b+c)/a,(c+a)/b,(a+b)/care in A.P.

Answer»

SOLUTION :`1/a.1/B,1/C` are in A.P.`IMPLIES(a+b+c)/a,(a+b+c)/b,(a+b+c)/c` are in A.P. `implies(a+b+c)/a-1,(a+b+c)/b-1,(a+b+c)/c-1` are in A.P. `implies(b+c)/a,(c+a)/b,(a+b)/c` are in A.P.


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