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Ifequilibrium constant for reaction 2ABA, + B2, is 49, then the equilibrium constant forreactionAB-A2+-B2,will be2(2)20(4) 212(3) 49If equilibrium constants of reaction, N+02 |
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Answer» 49 bcoz in first reaction there is two ab and product produced in 1:1 ratio and in second eqn ab is 1 it converts in 1/2:1/2 your ans is wrong equilibrium constant for 1st is written as Keq = [A2]¹[B2]¹/[AB]² and for 2nd reaction it is K'eq = A2]½[B2]½/[AB] that is K'eq = √Keq = √49 = 7 option 1 |
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